KE
Karl Exler
Thu, Jan 4, 2024 3:54 PM
Dear all
what must I do to "cut away" the parts outside the tube ?
Thanks Karl
include <bosl2/std.scad>
$fn=50;
l=100;
b=30;
s=3;
w=8;
for (i=[0:10:w*10])
translate([0,0,i])
schraege();
translate([0,0,l/2-7])
xrot(90)
tube(h=b, ir=(l-2)/2, wall=4);
module schraege()
{
rotate ([40,0,0])
linear_extrude(s)
square([l,b],center=true);
};
Dear all
what must I do to "cut away" the parts outside the tube ?
Thanks Karl
include <bosl2/std.scad>
$fn=50;
l=100;
b=30;
s=3;
w=8;
for (i=[0:10:w*10])
translate([0,0,i])
schraege();
translate([0,0,l/2-7])
xrot(90)
tube(h=b, ir=(l-2)/2, wall=4);
module schraege()
{
rotate ([40,0,0])
linear_extrude(s)
square([l,b],center=true);
};
DP
Dan Perry
Thu, Jan 4, 2024 4:11 PM
I think this is what you're looking for:
intersection() {
for (i=[0:10:w*10])
translate([0,0,i]) schraege();
-
hull() translate([0,0,l/2-7]) xrot(90) tube(h=b, ir=(l-2)/2,
wall=4);}*
On Thu, Jan 4, 2024 at 3:55 PM Karl Exler via Discuss <
discuss@lists.openscad.org> wrote:
Dear all
what must I do to "cut away" the parts outside the tube ?
Thanks Karl
include <bosl2/std.scad>
$fn=50;
l=100;
b=30;
s=3;
w=8;
for (i=[0:10:w*10])
translate([0,0,i])
schraege();
translate([0,0,l/2-7])
xrot(90)
tube(h=b, ir=(l-2)/2, wall=4);
module schraege()
{
rotate ([40,0,0])
linear_extrude(s)
square([l,b],center=true);
};
OpenSCAD mailing list
To unsubscribe send an email to discuss-leave@lists.openscad.org
I think this is what you're looking for:
*intersection() {*
for (i=[0:10:w*10])
translate([0,0,i]) schraege();
* hull() translate([0,0,l/2-7]) xrot(90) tube(h=b, ir=(l-2)/2,
wall=4);}*
On Thu, Jan 4, 2024 at 3:55 PM Karl Exler via Discuss <
discuss@lists.openscad.org> wrote:
> Dear all
> what must I do to "cut away" the parts outside the tube ?
>
> Thanks Karl
>
>
> include <bosl2/std.scad>
>
> $fn=50;
> l=100;
> b=30;
> s=3;
> w=8;
>
> for (i=[0:10:w*10])
> translate([0,0,i])
> schraege();
>
> translate([0,0,l/2-7])
> xrot(90)
> tube(h=b, ir=(l-2)/2, wall=4);
>
> module schraege()
> {
> rotate ([40,0,0])
> linear_extrude(s)
> square([l,b],center=true);
> };
>
> _______________________________________________
> OpenSCAD mailing list
> To unsubscribe send an email to discuss-leave@lists.openscad.org
>
KE
Karl Exler
Thu, Jan 4, 2024 5:23 PM
it works, when I add the part with the tube again after your proposal.
What I do not understand is how hull() works here?? In the cheat-sheet
it is used with 2 circles.. I can imagine that hull () {object, object,
object} draws a shape around to or more geometric parts... But here it
is used () "alone".
It works-- but I don't understand why :-|
Thanks for patience with an old man
Karl
Am 04.01.24 um 17:11 schrieb Dan Perry via Discuss:
I think this is what you're looking for:
intersection() {
for (i=[0:10:w10])
translate([0,0,i]) schraege();
* hull() translate([0,0,l/2-7]) xrot(90) tube(h=b, ir=(l-2)/2,
wall=4);
}
*
*
translate([0,0,l/2-7])
xrot(90)
tube(h=b, ir=(l-2)/2, wall=4);
On Thu, Jan 4, 2024 at 3:55 PM Karl Exler via Discuss
discuss@lists.openscad.org wrote:
Dear all
what must I do to "cut away" the parts outside the tube ?
Thanks Karl
include <bosl2/std.scad>
$fn=50;
l=100;
b=30;
s=3;
w=8;
for (i=[0:10:w*10])
translate([0,0,i])
schraege();
translate([0,0,l/2-7])
xrot(90)
tube(h=b, ir=(l-2)/2, wall=4);
module schraege()
{
rotate ([40,0,0])
linear_extrude(s)
square([l,b],center=true);
};
_______________________________________________
OpenSCAD mailing list
To unsubscribe send an email to discuss-leave@lists.openscad.org
OpenSCAD mailing list
To unsubscribe send an email todiscuss-leave@lists.openscad.org
it works, when I add the part with the tube again after your proposal.
What I do not understand is how hull() works here?? In the cheat-sheet
it is used with 2 circles.. I can imagine that hull () {object, object,
object} draws a shape around to or more geometric parts... But here it
is used () "alone".
It works-- but I don't understand why :-|
Thanks for patience with an old man
Karl
Am 04.01.24 um 17:11 schrieb Dan Perry via Discuss:
> I think this is what you're looking for:
>
> *intersection() {*
> for (i=[0:10:w*10])
> translate([0,0,i]) schraege();
> * hull() translate([0,0,l/2-7]) xrot(90) tube(h=b, ir=(l-2)/2,
> wall=4);
> }*
> *
> *
> translate([0,0,l/2-7])
> xrot(90)
> tube(h=b, ir=(l-2)/2, wall=4);
> On Thu, Jan 4, 2024 at 3:55 PM Karl Exler via Discuss
> <discuss@lists.openscad.org> wrote:
>
> Dear all
> what must I do to "cut away" the parts outside the tube ?
>
> Thanks Karl
>
>
> include <bosl2/std.scad>
>
> $fn=50;
> l=100;
> b=30;
> s=3;
> w=8;
>
> for (i=[0:10:w*10])
> translate([0,0,i])
> schraege();
>
> translate([0,0,l/2-7])
> xrot(90)
> tube(h=b, ir=(l-2)/2, wall=4);
>
> module schraege()
> {
> rotate ([40,0,0])
> linear_extrude(s)
> square([l,b],center=true);
> };
>
> _______________________________________________
> OpenSCAD mailing list
> To unsubscribe send an email to discuss-leave@lists.openscad.org
>
>
> _______________________________________________
> OpenSCAD mailing list
> To unsubscribe send an email todiscuss-leave@lists.openscad.org
DP
Dan Perry
Thu, Jan 4, 2024 5:29 PM
In this case, hull() calculates the enclosing shape of a single object.
Dan
On Thu, Jan 4, 2024 at 5:23 PM Karl Exler via Discuss <
discuss@lists.openscad.org> wrote:
it works, when I add the part with the tube again after your proposal.
What I do not understand is how hull() works here?? In the cheat-sheet it
is used with 2 circles.. I can imagine that hull () {object, object,
object} draws a shape around to or more geometric parts... But here it is
used () "alone".
It works-- but I don't understand why :-|
Thanks for patience with an old man
Karl
Am 04.01.24 um 17:11 schrieb Dan Perry via Discuss:
I think this is what you're looking for:
intersection() {
for (i=[0:10:w*10])
translate([0,0,i]) schraege();
-
hull() translate([0,0,l/2-7]) xrot(90) tube(h=b, ir=(l-2)/2,
wall=4); }*
translate([0,0,l/2-7])
xrot(90)
tube(h=b, ir=(l-2)/2, wall=4);
On Thu, Jan 4, 2024 at 3:55 PM Karl Exler via Discuss <
discuss@lists.openscad.org> wrote:
Dear all
what must I do to "cut away" the parts outside the tube ?
Thanks Karl
include <bosl2/std.scad>
$fn=50;
l=100;
b=30;
s=3;
w=8;
for (i=[0:10:w*10])
translate([0,0,i])
schraege();
translate([0,0,l/2-7])
xrot(90)
tube(h=b, ir=(l-2)/2, wall=4);
module schraege()
{
rotate ([40,0,0])
linear_extrude(s)
square([l,b],center=true);
};
OpenSCAD mailing list
To unsubscribe send an email to discuss-leave@lists.openscad.org
In this case, hull() calculates the enclosing shape of a single object.
Dan
On Thu, Jan 4, 2024 at 5:23 PM Karl Exler via Discuss <
discuss@lists.openscad.org> wrote:
> it works, when I add the part with the tube again after your proposal.
>
> What I do not understand is how hull() works here?? In the cheat-sheet it
> is used with 2 circles.. I can imagine that hull () {object, object,
> object} draws a shape around to or more geometric parts... But here it is
> used () "alone".
>
> It works-- but I don't understand why :-|
> Thanks for patience with an old man
>
> Karl
>
>
>
> Am 04.01.24 um 17:11 schrieb Dan Perry via Discuss:
>
> I think this is what you're looking for:
>
> *intersection() {*
> for (i=[0:10:w*10])
> translate([0,0,i]) schraege();
>
> * hull() translate([0,0,l/2-7]) xrot(90) tube(h=b, ir=(l-2)/2,
> wall=4); }*
>
> translate([0,0,l/2-7])
> xrot(90)
> tube(h=b, ir=(l-2)/2, wall=4);
>
>
>
> On Thu, Jan 4, 2024 at 3:55 PM Karl Exler via Discuss <
> discuss@lists.openscad.org> wrote:
>
>> Dear all
>> what must I do to "cut away" the parts outside the tube ?
>>
>> Thanks Karl
>>
>>
>> include <bosl2/std.scad>
>>
>> $fn=50;
>> l=100;
>> b=30;
>> s=3;
>> w=8;
>>
>> for (i=[0:10:w*10])
>> translate([0,0,i])
>> schraege();
>>
>> translate([0,0,l/2-7])
>> xrot(90)
>> tube(h=b, ir=(l-2)/2, wall=4);
>>
>> module schraege()
>> {
>> rotate ([40,0,0])
>> linear_extrude(s)
>> square([l,b],center=true);
>> };
>>
>> _______________________________________________
>> OpenSCAD mailing list
>> To unsubscribe send an email to discuss-leave@lists.openscad.org
>>
>
> _______________________________________________
> OpenSCAD mailing list
> To unsubscribe send an email to discuss-leave@lists.openscad.org
>
> _______________________________________________
> OpenSCAD mailing list
> To unsubscribe send an email to discuss-leave@lists.openscad.org
>
AM
Adrian Mariano
Thu, Jan 4, 2024 5:33 PM
hull() makes the smallest convex object containing all its arguments. With
a tube as the argument it fills in the inside to make a cylinder. A more
direct solution to you problem is to intersect with a cylinder of the
appropriate size directly.
On Thu, Jan 4, 2024, 12:23 Karl Exler via Discuss <
discuss@lists.openscad.org> wrote:
it works, when I add the part with the tube again after your proposal.
What I do not understand is how hull() works here?? In the cheat-sheet it
is used with 2 circles.. I can imagine that hull () {object, object,
object} draws a shape around to or more geometric parts... But here it is
used () "alone".
It works-- but I don't understand why :-|
Thanks for patience with an old man
Karl
Am 04.01.24 um 17:11 schrieb Dan Perry via Discuss:
I think this is what you're looking for:
intersection() {
for (i=[0:10:w*10])
translate([0,0,i]) schraege();
-
hull() translate([0,0,l/2-7]) xrot(90) tube(h=b, ir=(l-2)/2,
wall=4); }*
translate([0,0,l/2-7])
xrot(90)
tube(h=b, ir=(l-2)/2, wall=4);
On Thu, Jan 4, 2024 at 3:55 PM Karl Exler via Discuss <
discuss@lists.openscad.org> wrote:
Dear all
what must I do to "cut away" the parts outside the tube ?
Thanks Karl
include <bosl2/std.scad>
$fn=50;
l=100;
b=30;
s=3;
w=8;
for (i=[0:10:w*10])
translate([0,0,i])
schraege();
translate([0,0,l/2-7])
xrot(90)
tube(h=b, ir=(l-2)/2, wall=4);
module schraege()
{
rotate ([40,0,0])
linear_extrude(s)
square([l,b],center=true);
};
OpenSCAD mailing list
To unsubscribe send an email to discuss-leave@lists.openscad.org
hull() makes the smallest convex object containing all its arguments. With
a tube as the argument it fills in the inside to make a cylinder. A more
direct solution to you problem is to intersect with a cylinder of the
appropriate size directly.
On Thu, Jan 4, 2024, 12:23 Karl Exler via Discuss <
discuss@lists.openscad.org> wrote:
> it works, when I add the part with the tube again after your proposal.
>
> What I do not understand is how hull() works here?? In the cheat-sheet it
> is used with 2 circles.. I can imagine that hull () {object, object,
> object} draws a shape around to or more geometric parts... But here it is
> used () "alone".
>
> It works-- but I don't understand why :-|
> Thanks for patience with an old man
>
> Karl
>
>
>
> Am 04.01.24 um 17:11 schrieb Dan Perry via Discuss:
>
> I think this is what you're looking for:
>
> *intersection() {*
> for (i=[0:10:w*10])
> translate([0,0,i]) schraege();
>
> * hull() translate([0,0,l/2-7]) xrot(90) tube(h=b, ir=(l-2)/2,
> wall=4); }*
>
> translate([0,0,l/2-7])
> xrot(90)
> tube(h=b, ir=(l-2)/2, wall=4);
>
>
>
> On Thu, Jan 4, 2024 at 3:55 PM Karl Exler via Discuss <
> discuss@lists.openscad.org> wrote:
>
>> Dear all
>> what must I do to "cut away" the parts outside the tube ?
>>
>> Thanks Karl
>>
>>
>> include <bosl2/std.scad>
>>
>> $fn=50;
>> l=100;
>> b=30;
>> s=3;
>> w=8;
>>
>> for (i=[0:10:w*10])
>> translate([0,0,i])
>> schraege();
>>
>> translate([0,0,l/2-7])
>> xrot(90)
>> tube(h=b, ir=(l-2)/2, wall=4);
>>
>> module schraege()
>> {
>> rotate ([40,0,0])
>> linear_extrude(s)
>> square([l,b],center=true);
>> };
>>
>> _______________________________________________
>> OpenSCAD mailing list
>> To unsubscribe send an email to discuss-leave@lists.openscad.org
>>
>
> _______________________________________________
> OpenSCAD mailing list
> To unsubscribe send an email to discuss-leave@lists.openscad.org
>
> _______________________________________________
> OpenSCAD mailing list
> To unsubscribe send an email to discuss-leave@lists.openscad.org
>
K
Ken
Fri, Jan 5, 2024 6:10 AM
My simplistic take on this Karl- just wrap yours up in a union, then
difference another slightly larger tube.
include <bosl2/std.scad>
$fn=50;
l=100;
b=30;
s=3;
w=8;
difference()
{
union()
{
for (i=[0:10:w*10])
translate([0,0,i])
schraege();
translate([0,0,l/2-7])
xrot(90)
tube(h=b, ir=(l-2)/2, wall=4);
}
translate([0,0,l/2-7])
xrot(90)
tube(h=b, ir=(l+6)/2, wall=20);
}
module schraege()
{
rotate ([40,0,0])
linear_extrude(s)
square([l,b],center=true);
};
On 2024-01-05 02:54, Karl Exler via Discuss wrote:
Dear all
what must I do to "cut away" the parts outside the tube ?
Thanks Karl
A baby can be defined as an ego with a noise at one end and a smell at the other.
Your job as parents is to teach them to control all three.
My job as a grandad is to tell you how you are doing it all wrong!
My simplistic take on this Karl- just wrap yours up in a union, then
difference another slightly larger tube.
include <bosl2/std.scad>
$fn=50;
l=100;
b=30;
s=3;
w=8;
difference()
{
union()
{
for (i=[0:10:w*10])
translate([0,0,i])
schraege();
translate([0,0,l/2-7])
xrot(90)
tube(h=b, ir=(l-2)/2, wall=4);
}
translate([0,0,l/2-7])
xrot(90)
tube(h=b, ir=(l+6)/2, wall=20);
}
module schraege()
{
rotate ([40,0,0])
linear_extrude(s)
square([l,b],center=true);
};
On 2024-01-05 02:54, Karl Exler via Discuss wrote:
> Dear all
> what must I do to "cut away" the parts outside the tube ?
>
> Thanks Karl
--
Cheers, Ken
bats059@gmail.com
https://vk7krj.com
https://vk7krj.com/running.html
----------------------------------------
A baby can be defined as an ego with a noise at one end and a smell at the other.
Your job as parents is to teach them to control all three.
My job as a grandad is to tell you how you are doing it all wrong!
KE
Karl Exler
Fri, Jan 5, 2024 7:52 AM
yeah... this is how my brain works.... thank you Ken.
and thank YOU Dan ;-)
KR Karl
Am 05.01.24 um 07:10 schrieb Ken via Discuss:
My simplistic take on this Karl- just wrap yours up in a union, then
difference another slightly larger tube.
include <bosl2/std.scad>
$fn=50;
l=100;
b=30;
s=3;
w=8;
difference()
{
union()
{
for (i=[0:10:w*10])
translate([0,0,i])
schraege();
translate([0,0,l/2-7])
xrot(90)
tube(h=b, ir=(l-2)/2, wall=4);
}
translate([0,0,l/2-7])
xrot(90)
tube(h=b, ir=(l+6)/2, wall=20);
}
module schraege()
{
rotate ([40,0,0])
linear_extrude(s)
square([l,b],center=true);
};
On 2024-01-05 02:54, Karl Exler via Discuss wrote:
Dear all
what must I do to "cut away" the parts outside the tube ?
Thanks Karl
A baby can be defined as an ego with a noise at one end and a smell at the other.
Your job as parents is to teach them to control all three.
My job as a grandad is to tell you how you are doing it all wrong!
OpenSCAD mailing list
To unsubscribe send an email todiscuss-leave@lists.openscad.org
yeah... this is how my brain works.... thank you Ken.
and thank YOU Dan ;-)
KR Karl
Am 05.01.24 um 07:10 schrieb Ken via Discuss:
>
> My simplistic take on this Karl- just wrap yours up in a union, then
> difference another slightly larger tube.
>
> include <bosl2/std.scad>
>
> $fn=50;
> l=100;
> b=30;
> s=3;
> w=8;
>
> difference()
> {
> union()
> {
> for (i=[0:10:w*10])
> translate([0,0,i])
> schraege();
> translate([0,0,l/2-7])
> xrot(90)
> tube(h=b, ir=(l-2)/2, wall=4);
> }
> translate([0,0,l/2-7])
> xrot(90)
> tube(h=b, ir=(l+6)/2, wall=20);
> }
>
> module schraege()
> {
> rotate ([40,0,0])
> linear_extrude(s)
> square([l,b],center=true);
> };
>
>
>
> On 2024-01-05 02:54, Karl Exler via Discuss wrote:
>> Dear all
>> what must I do to "cut away" the parts outside the tube ?
>>
>> Thanks Karl
> --
> Cheers, Ken
> bats059@gmail.com
> https://vk7krj.com
> https://vk7krj.com/running.html
> ----------------------------------------
> A baby can be defined as an ego with a noise at one end and a smell at the other.
> Your job as parents is to teach them to control all three.
> My job as a grandad is to tell you how you are doing it all wrong!
>
> _______________________________________________
> OpenSCAD mailing list
> To unsubscribe send an email todiscuss-leave@lists.openscad.org
