I am trying to do something in a function one of n ways (in this case one
of four ways).
First I tried doing a ternary operator nested twice (but it didn't seem to
like the syntax) and then I tried if statements.
If I have a function and what it does is dependent on a variable with n
possible values, is there some way to do it inside that function? What I
did in the past was to use the ternary operator once per helper but this
gets fairly tedious (it is easier to read but cumbersome).
I have an example where I tried to use "if" statements inside the function
(but it didn't work). Likewise nesting ternary operators inside that
function didn't work. I'd prefer not to create 6 helper functions (two
that use the ternary operator to decide which of the four end functions to
use)
function computeAngle(number, quadrant) =
let(baseAngle = atan(2/(number-1))
if (quadrant == 1) {
baseAngle;
}
else if (quadrant == 2) {
180 - baseAngle;
}
else if (quadrant == 3) {
180 + baseAngle;
}
else {
360 - baseAngle;
}
}
I am trying to do something in a function one of n ways (in this case one
of four ways).
First I tried doing a ternary operator nested twice (but it didn't seem to
like the syntax) and then I tried if statements.
If I have a function and what it does is dependent on a variable with n
possible values, is there some way to do it inside that function? What I
did in the past was to use the ternary operator once per helper but this
gets fairly tedious (it is easier to read but cumbersome).
I have an example where I tried to use "if" statements inside the function
(but it didn't work). Likewise nesting ternary operators inside that
function didn't work. I'd prefer not to create 6 helper functions (two
that use the ternary operator to decide which of the four end functions to
use)
function computeAngle(number, quadrant) =
let(baseAngle = atan(2/(number-1))
if (quadrant == 1) {
baseAngle;
}
else if (quadrant == 2) {
180 - baseAngle;
}
else if (quadrant == 3) {
180 + baseAngle;
}
else {
360 - baseAngle;
}
}
