Hi all; I have two math functions from which I am interested to generate a CAD model. Attached is a picture for what I am looking for but not sure how to do it. <http://forum.openscad.org/file/t2047/cad_model.png> The border line equations are given and the shaded black region is the one i want to generate. Also note that the third dimension does not matter for me as I am looking at a 2D case. It can be any flexible value. Thanks!! -- Sent from: http://forum.openscad.org/

You need to define a polygon <https://en.wikibooks.org/wiki/OpenSCAD_User_Manual/Using_the_2D_Subsystem#polygon> by its vertices. Something like: verts = [for(i=[0:nverts-1]) [ i/verts, f(i/nverts) ] ]; polygon(verts); This would be the upper part. 2018-01-10 13:32 GMT-02:00 Katt <saideep.pavuluri@pet.hw.ac.uk>: > Hi all; > > I have two math functions from which I am interested to generate a CAD > model. > > Attached is a picture for what I am looking for but not sure how to do it. > <http://forum.openscad.org/file/t2047/cad_model.png> > > The border line equations are given and the shaded black region is the one > i > want to generate. Also note that the third dimension does not matter for me > as I am looking at a 2D case. It can be any flexible value. > > Thanks!! > > > > > > -- > Sent from: http://forum.openscad.org/ > > _______________________________________________ > OpenSCAD mailing list > Discuss@lists.openscad.org > http://lists.openscad.org/mailman/listinfo/discuss_lists.openscad.org >

nverts = 10;
scalex = 8;
verts = concat(
                [for(i=[0:nverts-1])    [ scalex*i/nverts,  f(i/nverts)

There was a typo in my previous code. To get a symetrical shape, given the function f defined in the interval [0,1]: nverts = 10; scalex = 8; verts = concat( [for(i=[0:nverts-1]) [ scalex*i/nverts, f(i/nverts) ] ], [for(i=[nverts-1:-1:0]) [ scalex*i/nverts, -f(i/nverts) ] ] ); polygon(verts); 2018-01-10 13:45 GMT-02:00 Ronaldo Persiano <rcmpersiano@gmail.com>: > You need to define a polygon > <https://en.wikibooks.org/wiki/OpenSCAD_User_Manual/Using_the_2D_Subsystem#polygon> > by its vertices. Something like: > > verts = [for(i=[0:nverts-1]) [ i/verts, f(i/nverts) ] ]; > polygon(verts); > > > This would be the upper part. > > 2018-01-10 13:32 GMT-02:00 Katt <saideep.pavuluri@pet.hw.ac.uk>: > >> Hi all; >> >> I have two math functions from which I am interested to generate a CAD >> model. >> >> Attached is a picture for what I am looking for but not sure how to do it. >> <http://forum.openscad.org/file/t2047/cad_model.png> >> >> The border line equations are given and the shaded black region is the >> one i >> want to generate. Also note that the third dimension does not matter for >> me >> as I am looking at a 2D case. It can be any flexible value. >> >> Thanks!! >> >> >> >> >> >> -- >> Sent from: http://forum.openscad.org/ >> >> _______________________________________________ >> OpenSCAD mailing list >> Discuss@lists.openscad.org >> http://lists.openscad.org/mailman/listinfo/discuss_lists.openscad.org >> > >

Just for completeness, in the dev snapshot version concat() is not needed for this case anymore. It's enough to simply write: verts = [ for(i=[0:nverts-1]) [ scalex*i/nverts, f(i/nverts) ], for(i=[nverts-1:-1:0]) [ scalex*i/nverts, -f(i/nverts) ] ]; ciao, Torsten.

Here is some code with a function added for the y coord. <http://forum.openscad.org/file/t1309/poly.jpg> -- Sent from: http://forum.openscad.org/