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Sweep with easing equations

R
Ronaldo
Sun, Jan 15, 2017 1:17 AM

Benjamin-2 wrote

On 14/01/17 16:41, Ronaldo wrote:
An outCirc function in my example would have been better than an outQuad
but still behind your solution:

As a matter of fact, my fillet function reproduces an circular arc as you
can see by:

polygon([for(i=[0:10]) [i*i/10/10, fillet(i/10)]]);

The quadratic step size just adds a better resolution at one end. If you
define height and delt equal the circular fillet becomes apparent.
Otherwise, it is eliptical.

--
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Benjamin-2 wrote > On 14/01/17 16:41, Ronaldo wrote: > An outCirc function in my example would have been better than an outQuad > but still behind your solution: As a matter of fact, my fillet function reproduces an circular arc as you can see by: > polygon([for(i=[0:10]) [i*i/10/10, fillet(i/10)]]); The quadratic step size just adds a better resolution at one end. If you define height and delt equal the circular fillet becomes apparent. Otherwise, it is eliptical. -- View this message in context: http://forum.openscad.org/Sweep-with-easing-equations-tp20075p20087.html Sent from the OpenSCAD mailing list archive at Nabble.com.